Suzanne asked me explain the solution to the final problem in last issue's IQ test. Here it is:
A fish has a head 9" long. The tail is equal to the size of the head plus onehalf the size of the body. The body is the size of the head plus the tail. How long is the fish?
First, let's translate this into algebra. H = length of head, T = length of tail, and B = length of body. We are trying to determine H+B+T.
H = 9
T = H + B/2 = 9 + B/2
B = H + T = 9 + 9 + B/2 = 18 + B/2
So, if B = 18 + B/2 then:
{sub 18 from both sides} B18 = B/2
{mult both sides by 2} 2B36 = B
{sub B from both sides} B36 = 0
{add 36 to both sides} B = 36
If B=36 then T = 9+B/2 = 27
So the total length of the fish = Head + Body + Tail = 9 + 36 + 27 = 72.
For those of you fretting over any of the other questions, here are the answers. (I obtained them by cracking the program and peering inside ):
12
25
34
43
52
62
75
85
93
105
113
122
134
145
155
164
172
184
194
204
214
222
233
242
252
262
274
283
293
305
314
323
332
343
352
364
372
384
394
403
414
422
435
441
452
464
474
483
495
502
514
522
532
545
553
561
575
585
593
604
